Why is my Spring Boot autowired JPA Repository failing JUnit test?
Answers
My JUnit test is failing with the following error: "java.lang.IllegalArgumentException: Could not find field [userRepository] of type [null] on target [com.clearsoft.demo.UserResource@756b2d90]"
Here is the Test class:
@RunWith(SpringJUnit4ClassRunner.class)
@SpringApplicationConfiguration(classes = App.class)
@WebAppConfiguration
@IntegrationTest
public class UserResourceTest {
@Autowired
private UserRepository userRepository;
private MockMvc restUserMockMvc;
@Before
public void setup() {
UserResource userResource = new UserResource();
ReflectionTestUtils.setField(userResource, "userRepository", userRepository);
this.restUserMockMvc = MockMvcBuilders.standaloneSetup(userResource).build();
}
@Test
public void testGetExistingUser() throws Exception {
restUserMockMvc.perform(get("/user/foo")
.accept(MediaType.APPLICATION_JSON))
.andExpect(status().isOk())
.andExpect(content().contentType("application/json"))
.andExpect(jsonPath("$.id").value(1));
}
}
And here is the UserResource service:
@RestController
public class UserResource {
@Autowired
UserRepository repository;
@RequestMapping(value = "/user/{email}", method = RequestMethod.GET)
User hello(@PathVariable("email") String email) {
return repository.findByEmailAddressAllIgnoringCase(email);
}
}
Here is the repository:
public interface UserRepository extends Repository<User, Long> {
Page<User> findAll(Pageable pageable);
User findByEmailAddressAllIgnoringCase(String emailAddress);
}
And here is the Entity:
@Entity
@Table(name = "users")
public class User implements Serializable {
/**
*
*/
private static final long serialVersionUID = -1680480089065575997L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "id")
private Integer id;
@Basic(optional = false)
@NotNull
@Size(min = 1, max = 255)
@Column(name = "email_address")
@Pattern(regexp = "[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\\."
+ "[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@"
+ "(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\\.)+[a-z0-9]"
+ "(?:[a-z0-9-]*[a-z0-9])?", message = "{invalid.email}")
private String emailAddress;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getEmailAddress() {
return emailAddress;
}
public void setEmailAddress(String emailAddress) {
this.emailAddress = emailAddress;
}
}
Here is the App class:
@SpringBootApplication
public class App implements CommandLineRunner {
@Autowired
UserRepository repository;
public static void main(String[] args) {
SpringApplication.run(App.class);
}
@Override
public void run(String... strings) throws Exception {
System.out.println("**************** RUN RUN RUN RUN");
for (User user : repository.findAll(null)) {
System.out.println("****************" + user.getEmailAddress());
}
}
}
Answers
Exception comes from this line:
ReflectionTestUtils.setField(userResource, "userRepository", userRepository);
Second parameter of setField method is a field name. UserResource has field "repository" - not "userRepository" as you try to set in your test.
